Calculate the radius of curvature of an equiconvex lens of refractive index 1.5
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We know that the lens makers formula for a concave lens as follows: where f is the focal length; μ = μ2/μ1 is refractive index of material of the lens with respect to the surrounding medium; R1 and R2 are radius of curvature of two concave spherical refracting surfaces. Now, it is given that the lens is an equi-convex lens, that is, R1 = - R2 Therefore, Given: • Refractive index of lens is μ2 =1.5. • Refractive index of medium is μ1 =1.4. • Power of the lens = –5 D. Therefore, the focal length is Therefore, Hence, the radius of curvature of the given equi-concave lens is 2.857 cm.Read more on Sarthaks.com - https://www.sarthaks.com/544627/calculate-the-radius-of-curvature-of-an-equi-concave-lens-of-refractive-index-1-5
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