Question

calculate the radius of third bohrorbit of hydrogen atom and the energy of the electron in that orbit . given h= 6.625×10 power -34 js , e= 1.6 × 10 power -19 C , m= 9.1× 10 power -31 kg , c = 3×10 power 8 ms power -1 and enot = 8.85 × 10 power -12 fm power -1♡♡♡ iss ques ko baar baar type krke fingers ghss gyi hai prr koi ans nhi de rha ..PlZ ANS DE DO KOI

Answer 1

Radius of third orbit of hydrogen atom :- r = n²h² / 4pi²Kme² ( where, n = number of bohr orbits & K = 9×10"9 Nm²/C²)

= 3²×(6.625×10-³4)²/ 4×(3.14)²×9×10"9×9.1×10-³¹×(1.6×10-¹9)²

r = 0.0478×10"-8

Total energy of bohr 3rd orbital is given by:-

T.E. = -13.6/n² eV where, n = number of bohr Orbits.

= -13.6/3² eV

= 1.51 eV

(Note:- In this answer, 10"9 & 10"8 & 10-³4 = 10 raise to power 9, 8 and - 34)