Question

Calculate the radius ratio of 3rd and 5th orbit of He+ ​

Answer 1

$\huge\underline\green{\sf Answer:-}$

$\large{\boxed{\sf r_{3}:r_{5}=9:25}}$

$\huge\underline\green{\sf Solution:-}$

Given :-

$\sf{n_{1}}$ = 3

$\sf{n_{2}}$ = 5

Atomic no.of He (Z) = 2

FORMULA TO CALCULATE RADIUS IS :-

$\large{\boxed{\sf r=0.529×{\frac{{n}^{2}}{Z}}}}$

$\large{\sf r_{3}=0.529×{\frac{{3}^{2}}{2}}}$

$\large\implies{\sf 0.529×{\frac{9}{2}}}$

And

$\large{\sf r_{5}=0.529×{\frac{{5}^{2}}{2}}}$

$\large\implies{\sf 0.529×{\frac{25}{2}}}$

Therefore,

$\large{\sf {\frac{r_{3}}{r_{5}}}={\frac{0.529×9/2}{0.529×25/2}}}$

$\large\implies{\sf {\frac{9}{25}}}$

$\huge\red{\boxed{\sf r_{3}:r_{5}=9:25}}$

Answer 2

The correct answer is  $\frac{9}{25}$.

Given: 3rd and 5th orbit of $He^{+}$.

To Find: Ratio of radius.

Solution:

$R=0.529*\frac{n^{2} }{Z}$  A°

For 3rd and 5th orbit only n will change in the formula rest all will remain same.

So, ratio = $\frac{n_{1}^{2} }{n_{2} ^{2} }$

= $\frac{3^{2} }{5^{2} }$

= $\frac{9}{25}$

Hence, the ratio of radius is  $\frac{9}{25}$.

#SPJ3