Question

calculate the ratio by mass of atoms present in a molecule of carbon dioxide

Answer 1

Mass of C in CO2 is 12
Mass of O in CO2 is 2x16= 32
Ratio=12:32=3:8

Answer 2

The 'ratio by mass of atoms' present in the Carbon-dioxide molecule is 3:8.

Explanation:

• The given molecule is carbon dioxide molecule and its chemical formula is $CO_2$.

• This molecule is having only a carbon atom but there are two oxygen atoms in it.

• Since there is only one carbon but there are two oxygen the total mass of Carbon is equal to 12

• The total mass of Oxygen is equal to 32.

• Now, we have to divide these two respectively to obtain the ratio. So, 12:32 will be equal to 3:8.

        Mass of carbon in $CO_2$ is 12

        Mass of oxygen in $CO_2$ is $16\times 2$ = 32

        Therefore the ratio between them is

        $\frac {12}{32}=3:8$.

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