Calculate the ratio of avg ke of one molecule of diatomic rigid and diatomic elastic at temperature 150c
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As per the kinetic theory of gases, the active vitality of any atom or molecule, whether it is poly-atomic, mono-atomic or diatomic, is equal to 3/2 kbT, where kb is the Boltzmann Constant.
Average energy is the result of translational and rotational energies.
Average K.E. (rigid)/ Average K.E. (elastic) = 3/2kT / 5kT= 0.3
If we calculate it with respect to lighter and denser gases then the ratio will be 5:7
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