Question

calculate the ratio of kinetic energy of 3g of H2 and 4g of O2 at a given temperature.​

Answer 1

In question the 4g of O2 and 3g of H2 is given

We use kinetic formula as:

Avrg:K.E=2/3 KT

As H2=2moles And O=32moles .

We get

3/2=1.5

4/32=0.125

In Ratio we get 1.5 :0.125

Answer 2

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Since the temperature is same for the two gases,we can write the ratio of kinetic energies is in the moles of ${H2}$: moles of ${O2}$.

$\frac{3g ofH2}{2g m^-1}$:$\frac{4g ofO2}{32g mol^-1}$=$\frac{3}{2}$:$\frac{1}{8}$=${12:1}$.