Question

Calculate the ratio of molecules present in 16gram of methane and 16 gram of oxygen

Answer 1

The number of molecules can be decided with the use of moles as 1 mole contains around 6.023* 10^23 molecules

the number of moles in a system is given by

GIVEN WEIGHT / GRAM MOLECULAR WEIGHT

1. 16 grams of methane   - methane's gmw is 16 grams so the number of moles is 16/16 which is 1. so, there are 1 mole of methane in 16 grams
2. the gmw of oxygen is 16 grams . so ,the number of moles of oxygen are 16/16 which is also 1

SO THE RATIO OF BOTH MOLECULES SHALL BE 1 /1 WHICH IS 1:1

HOPE THIS HELPED                                                                                                            

Answer 2

Answer:

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Explanation:

Molar mass of CH4 = 16u

No of moles = Mass given /molar mass

= 16/16=1 moles

1 mole = 6.022*10^23 molecules

Molar mass of O2 = 2*16=32u

No of moles =Mass given/ molar mass

= 16/32=0.5moles

0.5 moles =0.5*6.022*10^23 molecules

= 3.011*10^23 molecules

Ratio of CH4:O2 =6.022*10^23/3.011*10^23

=2:1