Question

Calculate the ratio of moles of 3.6g of water and 4.4g of carbon dioxide. Atomic mass of c=12, h=1u, o=16u.

Answer 1

Given mass of water = 3.6g

Molar mass of water = 18 g

moles of water = given mass/molar mass

= 3.6/18

= 0.2 moles

Given mass of carbon dioxide = 4.4g

Molar mass of carbon dioxide = 44 g

Moles of CO2 = Given mass / molar mass

= 4.4/44

= 0.1 moles

Therefore, ration of their moles = 0.2/0.1

= 2: 1