Question

calculate the ratio of momentum when
1. velocity of an object is double
2. mass of an object is halved
3. both mass and velocity are increased by three times

Answer 1

Momentum(M) = mass x velocity
                        = mv

1) M = 2mv
     ∴ ratio 1:2

2) M = 1/2(mv)
     ∴ ratio 1:1/2 = 2:1

3) M = 9mv
     ∴ ratio 1:9

Answer 2

Answer:

1.  $\frac{1}{2}$

2. $\frac{2}{1}$

3.  $\frac{1}{9}$

Explanation:

• Momentum of a body is defined as the product of mass and velocity with which the body is moving.
• We can also say that a body at rest has zero momentum or no momentum.
• Let that the momentum of body, P=mv.

1. When the velocity is doubled ,P=2mv                                                                              Therefore, $\frac{P_{o} }{P_{r} }$$=\frac{mv}{2mv}$ $=\frac{1}{2}$
2. When mass is halved, P=$\frac{mv}{2}$                                                                                       Therefore,, $\frac{P_{o} }{P_{r} }$ $=\frac{2mv}{mv}$ $=\frac{2}{1}$
3. Both mass and velocity is increased three times,  P=9mv                             Therefore, , $\frac{P_{o} }{P_{r} }$ =$\frac{mv}{9mv}$ $=\frac{1}{9}$

• Hence, the required ratio is as above.

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