Question

Calculate the ratio of t99.9% and t50% of a first order reaction

Answer 1

i think that 5 answer

Answer 2

The ratio of t99.9% and t50% of a first order reaction is 10: 1

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$k=\frac{0.693}{k}$

b) for completion of 99.9 % of reaction

$t=\frac{2.303}{k}\log\frac{100}{100-99.9}$

$t=\frac{2.303}{k}\log\frac{100}{100-99.9}$

$t=\frac{2.303}{k}\times 3$

$t_{99.9}=\frac{6.909}{k}$

The ratio of t99.9% and t50% of a first order reaction is 10: 1

Learn More about first order

brainly.in/question/4482242

brainly.in/question/4761487