Question

Calculate the ratio of the reaction of a convex bridge at the highest point to the reaction of a concave bridge at its lowest point when a car passes at 30 kmph and the radius of either bridge is 20 m.

Answer 1

     The forces acting on the car are weight mg  and normal reaction from the road on the bridge.  We ignore friction and Thrust force of engine for this calculation.  As the car is moving at uniform speed, friction and engine thrust are equal and opposite. They are perpendicular to radius and so  do not contribute to the centripetal force. 

        v = 30 kmph = 25/3 m/s

1) Convex: centripetal force :
           mg - N1 = m v² / R       =>  N1 = m (g - v^2/R) = m*235/36 N

2) Concave bridge:  
          N2 - mg = m v²/R      =>  N2 = m (g + v²/R) = m *485/36  N

Ratio:   N1/ N2 = 235/485 = 47/97

Answer 2

Answer:

0.48 : 1

Explanation:

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