Question

Calculate the relative molecular mass of:(1) CuSO4.5H2O (2) (NH4)2SO4 (3) CH3COONa (4) CHCl3 (5) (NH4)2 Cr2O7 Please give solution also

Answer 1

CuSO4.5H2O :
Cu = 63.5
S = 32
O = 16
H = 1

63.5+32+16×4+10+16×5
63.5+32+64+10+80
= 249.5g

(NH4)2SO4 :
N = 14
H = 1
S = 32
O = 16

14×2+1×8+32+16×4
28+8+32+64
= 132g

CH3COONa :
C = 12
H = 1
O = 16
Na = 23

12+1×3+12+16×2+23
12+3+12+32+23
= 82g

CHCl3 :
C = 12
H = 1
Cl = 35.5

12+1+35.5×3
12+1+106.5
= 119.5g

(NH4)2Cr2O7 :
N = 14
H = 1
Cr = 52
O = 16

14×2+1×8+52×2+16×7
28+8+104+112
= 252g




Hope it helps.......

Answer 2

Answer:

Explanation:

Here is the answer