solve question no. 1 please
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see diagram.
The angle of incidence is same at both interfaces, as the surfaces are parallel.
Critical angle for top interface/top reflection: Sin⁻¹ √2/2 = 45°
Critical angle for the bottom interface (2nd reflection)
Sin⁻¹ √3/2 = 60°
Hence, the angle of incidence must be more than or equal to 60° for total internal reflection to occur at both interfaces.
The angle of incidence is same at both interfaces, as the surfaces are parallel.
Critical angle for top interface/top reflection: Sin⁻¹ √2/2 = 45°
Critical angle for the bottom interface (2nd reflection)
Sin⁻¹ √3/2 = 60°
Hence, the angle of incidence must be more than or equal to 60° for total internal reflection to occur at both interfaces.
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kvnmurty:
click on red heart thanks above pls
wow , by your explanation this will be easy
great sir
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Great Answer sir
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