Calculate the required heat energy to convert 10 grams of ice at0 degrees Celsius to water at 0 degrees Celsius ( lantent heat of fusion of ice = 80 calories/ grams)
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Total heat absorbed
ΔH
fusion
+ΔH
temp.rise
+ΔH
vap.
=10×80+10×1×100+10×540=7200cal
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