Question

calculate the resistance of a copper wire of length 1 metre and area of cross section 2 millimetre square resistivity of copper is 1.7 * 10 to the power minus 8 ohm metre

Answer 1

hello friend...!!


• According to the questions, we should calculate the resistance of the copper wire

• we know that,

R = ΦL / A

where R denotes resistance, Φ denotes resistivity, L denotes length of the wire and A denotes area of cross section.

L = 1m

A = 2 mm^2 = 2 x 10^-6 m^2

Φ = 1.7 x 10^-8 ohm meter.

therefore,

R = ( 1.7 x 10^-8 x 1 ) / 2 x 10^-6

R = 0.85 x 10^-2

implies,

R = 8.5 x 10^-3 ohm.

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Hope it helps....!!

Answer 2

Hey!

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Length of the wire = 1m
Area of cross sectional area = 2 × 10^-6 m
Resistivity = 1.7 × 10^-8 Ωm

We know,

Resistance = Resistivity × Length / Area of cross sectional area

R = ρ × L / A

R = ( 1.7 × 10^-8 × 1) / 2 × 10^-6

R = [ 1.7 × 10^-8 - (-6) ] / 2

R = 1.7 × 10 ^ -2 / 2

R = 0.85 × 10^-2 ohm

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Hope it helps...!!!