Question

Calculate the resistance of a metal wire of length 2m and area of cross section 1.55*10to the power -6, if the resistivity of metal be 2.8*10to the power -8.

Answer 1

Answer:

RESISTANCE ( R ) = 36 × 10-³ Ω ( ohms)

Explanation:

★ CURRENT ELECTRICITY ★

★ GIVEN ;

» Length of Wire ( L ) = 2 m

» Area of Cross - Section ( A ) = 1.55 × 10^-6 m²

» RESISTIVITY ( p ) = 2.8 × 10^-8

★ RESISTANCE ( R ) = ???

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———— [ BY USING FORMULA ] ————

[ $r \: = \: p \: ( \: \frac{l}{a} \: )$ ]

★ R = 2.8 × 10^-8 × [ 2 / 155 × 10^-8 ]

» R = 2.8 × 10^-8 × [ 2 × 10^8 / 155 ]

» R = [ 2.8 × 2 ] / 155

» R = [ 5.6 ] / 155

» R = 0.036 Ω

★ » RESISTANCE ( R ) = 36 × 10-³ Ω « ★

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ANSWER :- HENCE ; RESISTANCE of wire of RESISTIVITY ( p ) is ;

♣ R = 36 × 10-³ Ω ♥

Answer 2

♋♋YOUR ANSWERS♍♍

✍ R = 36 × 10¯³ ohm

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EXPLANATION —

________we have__________

$R = p \frac{l}{A}$

___________________________

Here given,

Resistivity of metal p= 2.8 × 10^¯8

Length of wire l = 2 m

Area of cross section A = 1.5 ×10^¯6 m²

Putting the values

$R = (2.8 \times {10}^{ - 8} ) \times \frac{2}{1.5 \times {10}^{ - 6} }$

On solving

R = 0.036 ohm

R = 36 × 10¯³ ohm

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