calculate the resistance of an aluminium cable of length 10 km and diameter 2.0 mm if the resistivity of aluminium is 2.7 * 10^-8 ohm metre
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Resistance of Al =>135×10^-4 ohms
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R=ro X l/A
where, ro =2.7x10^-8ohm m
d=2x10^-3m ==> r=10^-3m ==>A=πr^2=πx10^-6 m^2
l=10x10^-3m
therefore, R=2.7x10^-8 X 10x10^-3 / πx10^-6 (where π=3.14)
R=0.8598x10^-4ohm(or)8.598x10^-1ohm
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where, ro =2.7x10^-8ohm m
d=2x10^-3m ==> r=10^-3m ==>A=πr^2=πx10^-6 m^2
l=10x10^-3m
therefore, R=2.7x10^-8 X 10x10^-3 / πx10^-6 (where π=3.14)
R=0.8598x10^-4ohm(or)8.598x10^-1ohm
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