Question

calculate the resistance of an aluminium cable of length 10 kilometre and diameter 2.0 mm if there is Satyawati of Aluminium is 2.7 into 10 power minus 8 over

Answer 1

Here , 
 L = 10000m
 D = 2mm
 r = D/2 = 1 × 10^(-3)m
 P = 2.7 × 10^(-8)ohm m
 R =  ?
 we know that , 
  R = pL/A
  A = πr²
  A = 22/7 × 1 × 10^[(-3)]²
  R = 2.7 × 10^(-8) × 1000 × 1/[ 22/7 × 1 × 10^[(-3)]² ]
  R = 85.9 ohm ≈ 86 ohm

Answer 2

Answer:

The resistance of the aluminum cable is 8.59Ω.

Explanation:

The cable's resistance is determined as follows:

$R=\rho\frac{l}{A}$     (1)

Where,

R=resistance of the cable

ρ=resistivity of the Aluminum cable

l=length of the cable

A=area of the cross-section of the cable

From the question we have,

ρ=2.7× 10⁻⁸

l=10km=10×10³m

The diameter of the cable=2mm=2×10⁻³m

The radius of the cable=1×10⁻³m

The area of the cross-section of the cable(A)=πr² (2)

$A=\pi\times (1\times 10^-^3)^2$

$A=3.14\times 10^-^6 m^2$    (3)

We get the following results by plugging the things into equation (1):

$R=2.7\times 10^-^8\times \frac{10\times 10^3}{3.14\times 10^-^6}$

$R=0.859\times 10$

$R=8.59\Omega$

Hence, the resistance of the aluminum cable is 8.59Ω.

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