In rectangle ABCD,the bisectors of angles B and C meet at point O,show that triangle OBC is an isoceles right triangles.
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All angles in a rectangle Are 90°
∴∠B=90°
∠OBC=90°/2 (Because of the angular bisecter which divides an
angle into half)
∠C=90°
∠OCB=90°/2
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IN ΔBOC
∠OCB=∠OBC=90°
∴Base angles of the triangle are equal
so the TRIANGLE is an ISOCELES TRIANGLE.
∴∠B=90°
∠OBC=90°/2 (Because of the angular bisecter which divides an
angle into half)
∠C=90°
∠OCB=90°/2
-----------------------------------------------
IN ΔBOC
∠OCB=∠OBC=90°
∴Base angles of the triangle are equal
so the TRIANGLE is an ISOCELES TRIANGLE.
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