Physics, asked by gangster14e, 3 months ago

Calculate the resistance of peace of wire o.50m long diameter 2. 74 × 10^-4 m. Specific resistence of the wire is 1.66* 10^_8 am. Also calculate it's conductance.

Answers

Answered by mahanteshgejji
1

Answer:

Conductance = 7 mho

Explanation:

length of wire  l =0.5 m

diameter d = 2.74 x 10⁻⁴ m

∴radius r = 1.37 x 10⁻⁴ m

Specific resistance ρ = 1.66 x 10⁻⁸ Ω m

C/S Area of wire  A = πr²= 3.14 x (1.37 x 10⁻⁴)²

Conductance = 1/R = A/ρl

                                = 3.14 x (1.37 x 10⁻⁴)²/1.66 x 10⁻⁸ x0.5

                                = 7.1 mho

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