Question

calculate the resistance pf a 50m length of wire of cross section area 0.01sqmm and of resistivity 5multply 10^-8

Answer 1

l = 50m
cross section area = 0.01 mm2
p= 5 ×10^-8

We know
R = p×l/a

R =

Answer 2

Answer:

Resistance of the wire is $R =25 \times 10^{-5}$ ohm.

Step-by-step explanation:

Given : A 50 m length of wire of cross section area 0.01 sq.mm and of resistivity $5 \times 10^{-8}$

To find : Calculate the resistance?

Solution :

The resistance formula,

$R = \rho\times \frac{l}{a}$

Where, R is the resistance

$\rho=5 \times 10^{-8}$ is the resistivity

l=50 m is the length of the wire

a=0.01 sq.m is the area of cross section

Substitute the values in the formula,

$R =5 \times 10^{-8}\times \frac{50}{0.01}$

$R =5 \times 10^{-8}\times 5 \times 10^{3}$

$R =25 \times 10^{-5}$

Therefore, Resistance of the wire is $R =25 \times 10^{-5}$ ohm.