Calculate the resistivity of a material of a wire 1 m long, 0.4 mm in diameter and having a resistance of 2 ohm.
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Answer:
length of wire, l = 1m
diameter of cross sectional area of wire , d = 0.4mm = 4 × 10^-4 m
so, cross sectional area of wire, A = πd²/4 = π(4 × 10^-4)²/4 = 4π × 10^-8 m²
resistance of wire, R = 2ohm.
we know,
where is resistivity or specific resistance of material of the wire.
or, 2 = × 1/{4π × 10^-8}
or, 2 × 4π × 10^-8 = .
or, = 8π × 10^-8 ohm.m
= 25.12 × 10^-8 ohm.m
= 2.512 × 10^-7 ohm.m
hence, resistivity of material is 2.512 × 10^-7 ohm.m
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