Calculate the residue obtained on strongly heating 2.76 gram of ag 203
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Ag2CO3 on strong heating decomposes as
2Ag2CO3(s)-4Ag(s)+2CO2(g)+O2(g)
Molar mass of Ag2CO3 =276g
Molar mass of Ag=108g
2 mol of Ag2CO3 gives 4 moles of Ag
552g of Ag2CO3 gives 432g of Ag(residue)
2.76g of Ag2CO3 gives
432/552*2.76=2.16g of Ag as residue
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