Question

Calculate the residue obtained on strongly heating 2.76 gram of ag 203

Answer 1

Answer:

Ag2CO3 on strong heating decomposes as

2Ag2CO3(s)-4Ag(s)+2CO2(g)+O2(g)

Molar mass of Ag2CO3 =276g

Molar mass of Ag=108g

2 mol of Ag2CO3 gives 4 moles of Ag

552g of Ag2CO3 gives 432g of Ag(residue)

2.76g of Ag2CO3 gives

432/552*2.76=2.16g of Ag as residue