Calculate the resistivity of a material of a wire 10 m long, 0.4 mm in diameter and having a resistance of 2ohm
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Answered by
26
Resistivity = R*A / L
Diameter = 0.4 mm = 0.0004 m
Radius = 0.0002 m = 0.2 * 10^-3
Area = πr^2
= 22/7 * 0.2 * 10^-3 * 0.2 * 10^-3
= 22/7 * 0.4 * 10^-7
= 1.26 * 10^-7
Resistance = 2 ohms
Length = 10m
Resistivity = (2) * (1.26 * 10^-7) / 10
= 2.52 * 10^-8 ohm meter
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Diameter = 0.4 mm = 0.0004 m
Radius = 0.0002 m = 0.2 * 10^-3
Area = πr^2
= 22/7 * 0.2 * 10^-3 * 0.2 * 10^-3
= 22/7 * 0.4 * 10^-7
= 1.26 * 10^-7
Resistance = 2 ohms
Length = 10m
Resistivity = (2) * (1.26 * 10^-7) / 10
= 2.52 * 10^-8 ohm meter
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Answered by
16
Answer:
resistivity = 6.28 × 10⁻⁷ Ωm
Explanation:
Diameter (d) = 0.4 mm
So, radius (r) = 0.4/2 = 0.2 mm
1 mm = 1/10 cm = 1/10 * 100 m = 10⁻³ m
Area (A) = πr² = 3.14 × (10⁻³)² = 3.14 × 10⁻⁶ m²
Length (L) = 10 m
Resistance (R) = 2 Ω
For further calculations, refer attachment.
Hence, resistivity = 6.28 × 10⁻⁷ Ωm
Attachments:
shrey200514:
why you both have different answers
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