Question

Calculate the resultant of three resistors (3 ohm, 4 ohm, 12 ohm) connected in parallel.

Answer 1

$\huge{\mathcal{\blue{\underline{Answer}}}}$

Resultant resistance of three resistors connected parallel

$= \frac{1}{r _{1} } + \frac{1}{ r_{2} } + \frac{1}{ r_{3} } \\ = \frac{1}{4} + \frac{1}{12} + \frac{1}{3} \\ = \frac{3 + 1 + 4}{12} = (\frac{8}{12} )ohm$

$\huge{\mathcal{\blue{\underline{0.7ohm}}}}$

Answer 2

Explanation:

Given:- R1 = 3 ohm.

R2 = 4 ohm.

R3 = 12 ohm.

since, resistors are connected in parallel

therefore, 1/ R equivalent = 1/R1 + 1/R2 + 1/R3

=. 1/3 + 1/4 + 1/12

= (12 + 9 + 3) / 36.

= 24/36

= 2/3

hence , 1/R equivalent = 2/3

therefore, R equivalent = 3/2.