Question

calculate the retarding potential to be applied to an electron to increase its de broglie wavelength of 1.75 Armstrong to 2.25 Armstrong​

Answer 1

use the formula, $\bf{\lambda=\frac{12.27}{\sqrt{V}}}$

where $\lambda$ denotes wavelength in Angstrom, V denotes potential.

when wavelength = 1.75 A°

then, √V1 = 12.27/1.75

or, V1 = (12.27/1.75)² ≈ 49 volts

when wavelength = 2.25 A°

then, √V2 = 12.27/2.25

or, V2 = (12.27/2.25)² ≈ 30 volts

question want to find retarding potential.

so, retarding potential = potential difference = V1 - V2 = 49 - 30 = 19 volts.

hence, retarding potential is 19 volts.

Answer 2

Answer:

Explanation:

This is the answer for this question