Question

calculate the rms speed of oxygen molecule at 27'c atomic mass of oxygen is 16

Answer 1

calculate the root mean square speed of-oxygen molecule at 27 c

Answer 2

The rms velocity is 483.5 ms⁻¹

The given temperature is, T= 27° C

Temperature in Kelvin = 273 + 27 = 300K

Given that, atomic mass of oxygen = 16

∴ Molecular weight of oxygen, <br> M = 2 × 16 = 32

⇒ R = 8.31 J mol⁻¹ K⁻¹

So, the rms velocity, C =  $\sqrt{\frac{3RT}{M} }$

                                      =  $\sqrt{\frac{3 * 8.31 * 300}{32} }$

​

                                       = 483.5ms

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