Question

calculate The RMS velocity of Sulphur dioxide at 27 degree Celsius​

Answer 1

Answer:

As,

Formula to calculate RMS is given by

$RMS = \sqrt{ \frac{3RT}{M} }$

Where T is the temperature in kelvin

and M is the mass of gas.

R is universal gas constant.

Now,

ln the given question the gas is Sulphur Dioxide which has molecular mass 64.

and temperature is given as 27°C = 300K.

So,

$RMS = \sqrt{ \frac{3 \times 8.31 \times 300}{64} } \\ \\ RMS = \sqrt{ \frac{7479}{64} } \\ \\ RMS = \frac{86.48}{8} \\ \\ RMS = 10.81$

Answer 2

Answer:

Given:-

Temperature T =27° C = 27 + 273 = 300 K.

To Find: Root mean square (RMS) speed of SO2.

Calculation: - Molecular mass of SO2, M = 32 + 2 × 16 = 64 g. - Universal gas constant, R = 8.314. - We know that R M S speed is given as: v (RMS) = ...

v (RMS) = 10.81 m/s. - SO the RMS speed of SO2 at 27° C is 10.81 m/s.l