Question

Calculate the rms velocity of sulphur dioxide molecules at NTP. Given that 22400 c.c of gas at NTP

weigh 64gm​

Answer 1

the answer to your question is 176

Answer 2

Given:

t = 22400c.c = 273

$M_m$ = 64gm

To Find:

the rms velocity of sulphur dioxide molecules at NTP

Solution:

$V_R_M_S$ = $\sqrt{\frac{3RT}{M_m} }$

         = $\sqrt{\frac{3\cdot 8.314\cdot 273}{64} }$

         = $326.18\frac{m}{s}$