Question

Calculate the shortest and longest wavelengths of Lyman series of hydrogen atom.
Given R= 1.097 x 107m-1.​

Answer 1

Answer:

1λ=R[122-1n22]

∴1λ=1.097×107[122-132]=1.097×107×536.

∴1λ=1.097×107[122-1∞2]=1.097×1074.

Answer 2

Answer:

R=117.379

Explanation:

because by multiplying both numbers