Physics, asked by divithk, 1 month ago

Calculate the shortest and longest wavelengths of Lyman series of hydrogen atom.
Given R= 1.097 x 107m-1.

Answers

Answered by rorsoni867

0

Answer:

1λ=R[122-1n22]

∴1λ=1.097×107[122-132]=1.097×107×536.

∴1λ=1.097×107[122-1∞2]=1.097×1074.

Answered by vyasronit927

0

Answer:

R=117.379

Explanation:

because by multiplying both numbers

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