Calculate the shortest wavelength in the balmer series of hydrogen atom. In which region (infrared, visible, ultraviolet) of hydrogen spectrum does this wavelength lie?
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Since, we know that for Balmer series,

For shortest wavelength in Balmer series, the spectral series is given by

1/$\lambda $ = R x 1/4
1/$\lambda $ = R/4
$\lambda $ = 4/R
$\lambda $ = 4 / 1.097 x ${{10}^{7}}$
$\lambda $ = 3.64 x ${{10}^{-7}}$ m
The lines of Balmer series are found in the visible part of the spectrum.

For shortest wavelength in Balmer series, the spectral series is given by

1/$\lambda $ = R x 1/4
1/$\lambda $ = R/4
$\lambda $ = 4/R
$\lambda $ = 4 / 1.097 x ${{10}^{7}}$
$\lambda $ = 3.64 x ${{10}^{-7}}$ m
The lines of Balmer series are found in the visible part of the spectrum.
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