Question

Calculate the single electrode potential of zinc electrode at 27°C in a solution of Zn2+ = 0.15M . E Zn/Zn 2+ = -0.76 V​

Answer 1

Answer:

E = 0.79135

Step-by-step explanation:

Zn→Zn^2 +2e^−

E=E^o − 0.0591/n log Q

= 0.7618− 0.0591/2log0.1

=> E=0.79135

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