calculate the slant height of a cone whose radius of the base and height are in the ratio 5:12 and it's volume is 2512cubic cm ( pi= 3.14)
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Given ratio of radius and height = 5:12
Let radius of cone = 5x and height of cone = 12x
Volume of cone = 1/3πr²h
2512 cm³ = 1/3*3.14*(5x)²*12x
2512 = 1/3*3.14*25x²*12x
2512 = 314x³
x³ = 2512/314 = 8
⇒ x = 2
radius of cone = 5x = 10 cm
height of cone = 12x = 24 cm
l² = h²+r²
l² = (24)² + (10)² = 576+100 = 676
⇒ l = 26 cm
slant height of cone = 26 cm
Let radius of cone = 5x and height of cone = 12x
Volume of cone = 1/3πr²h
2512 cm³ = 1/3*3.14*(5x)²*12x
2512 = 1/3*3.14*25x²*12x
2512 = 314x³
x³ = 2512/314 = 8
⇒ x = 2
radius of cone = 5x = 10 cm
height of cone = 12x = 24 cm
l² = h²+r²
l² = (24)² + (10)² = 576+100 = 676
⇒ l = 26 cm
slant height of cone = 26 cm
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