Chemistry, asked by nidhipoppins681, 10 months ago

Calculate the solubility of a2x3 in pure water assuming that neither type of ion reacts with water. The solubility product of a2x3,ksp = 1.1 * 10-23

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Answered by Anonymous

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Here,. A2X3 → 2A3+ + 3X2-. Now, Ksp = [A3+ ]2 [X2-]3 = 1.1x 10- 23. If the solubility of A2X3 is y then , [A3+ ]= 2y and [X2-] = 3y.

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