calculate the speed of an electron which has a wavelength of 450nm
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You need to use the equation: E = hc/lambda
E = Energy (joules)
h = Planck's constant (6.626 *10^-34 J/s)
c = the speed of light (2.997 *10^8 m/s)
lambda = the wavelength of light (convert to meters)
Of course if you want the answer in electron volts (eV) you have to convert it later.
So, E = (6.626*10^-34 x 2.997*10^8)/450*10^-9
= 4.413*10^-19 Joules
1 eV = 1.6*10^-19 Joules
Therefore the energy of a photon with a wavelength of 450 nm
= 2.76 eV
E = Energy (joules)
h = Planck's constant (6.626 *10^-34 J/s)
c = the speed of light (2.997 *10^8 m/s)
lambda = the wavelength of light (convert to meters)
Of course if you want the answer in electron volts (eV) you have to convert it later.
So, E = (6.626*10^-34 x 2.997*10^8)/450*10^-9
= 4.413*10^-19 Joules
1 eV = 1.6*10^-19 Joules
Therefore the energy of a photon with a wavelength of 450 nm
= 2.76 eV
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