Question

calculate the speed of an object when its initial speed is 4 metre per second and its acceleration is 3 metre per second squared time of object required to travel 60 second​

Answer 1

Given :

• An object when its initial speed is 4 m/s and its acceleration is 3 m/s² and time of object required to travel 60 seconds.

To Find :

• Final Velocity (v) = ?

Solution :

• Initial velocity = 4 m/s
• Acceleration = 3 m/s²
• Time = 60 seconds

• To answer any question to do with mass, acceleration, velocity ,etc. you can use one or more of this set of equations. They are called the 'kinematic' equations and They are really easy to re-arrange, when you need to find the 'unknown quantity', that the question is asking for. Below these equations I will show you the general problem solving strategy to solve these quickly and easily :]

The Kinematic Equations :

• v = u + at
• s = ut + ½ at²
• v² - u² = 2as
• Sₙₜₕ = u + a/2 (2n - 1)

By using first equation of motion we get :

→ v = u + at

Where,

• a is acceleration
• v is Final velocity
• u is Initial velocity
• t is time taken

Now, plug in the given values in above equation of motion :

→ v = 4 + 3 × 60

→ v = 4 + 180

→ v = 184 m/s

⛬ The Final velocity of an object is 184 m/s.

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

Calculate the speed of an object when its initial speed is 4 metre per second and its acceleration is 3 metre per second squared time of object required to travel 60 second

$\huge{\boxed{\rm{\red{Answer}}}}$

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• An object when its initial speed is 4 metre per second and its acceleration is 3 metres per second square { 3m/s² } and time of object required to travel 60 second.

⚪Initial velocity = 4 m/s

⚪Acceleration = 3 m/s²

⚪Time = 60 seconds

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• Velocity.

${\bigstar}\large{\boxed{\sf{\pink{Full \: solution}}}}$

What is kinematic equations ?

The kinematic equations are a set of equations that describe the motion of an object with constant acceleration.

Some kinematic equations ?

$\mapsto$ S nth = u + a/2 (2n-1)

$\mapsto$ v = u + at

$\mapsto$ s = ut + ½at²

$\mapsto$ v² - u² = 2as

$\large{By \: using \: 1st\: equation \: of \: motion}$

$\mapsto$ v = u + at

$\large{In \: this}$

$\implies$ $\large{\boxed{\sf{Time \: as \: t}}}$

$\implies$ $\large{\boxed{\sf{Acceleration \: as \: a}}}$

$\implies$ $\large{\boxed{\sf{Final \: velocity \: as \: v}}}$

$\implies$ $\large{\boxed{\sf{Initial \: velocity \: as \: u}}}$

$\large{Substituting \: the \: value \: we \: get}$

$\large{Values \: r \: already \: given}$

$\mapsto$ v = 4 + 3 × 60

According to BODMAS we have to solve 4 + 3 × 60

B = Bracket

O = Off means multiply

D = Division

M = Multiplication

A = Addition

S = Subtraction

$\mapsto$ v = 4 + 180

$\mapsto$ v = 184

Hence, 184 m/s is the velocity.

Answer is 184 m/s

@Itzbeautyqueen23

Hope it's helpful

Thank you :)