Calculate the speed of light in a medium whose critical angle is 45 o ?
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Now, listen to me that refractive index= 1/sin(critical angle). Now the refractive index = 1/1/21/2.
refractive index=root(2).
Now, speed of light in that medium is always 3* 108/refractive index.
So, 3*108/1.414 =2.121*108. m/sec.
refractive index=root(2).
Now, speed of light in that medium is always 3* 108/refractive index.
So, 3*108/1.414 =2.121*108. m/sec.
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