Calculate the speed of the tip of second's hand of a watch of length 1.5 cm
Answers
Answered by
373
Seconds HAND of watch completes 1 revolution in 60 sec ( 1min).
Time = t=60 sec
The length of seconds HAND of watch will be it's radius
r=1.5cm =1.5/100=0.015 m
DISTANCE covered = 2 * pi* r
= 2* 3.14 *0.015
Speed = distance/ time
= 2*3.14*0.015/60
=0.00157 m/ s
= 1.57 x 10 ^-3 m/s.
Therefore , speed of the tip of second's hand of a watch of length 1.5 cm is 1.57 x 10 ^-3 m/s.
Time = t=60 sec
The length of seconds HAND of watch will be it's radius
r=1.5cm =1.5/100=0.015 m
DISTANCE covered = 2 * pi* r
= 2* 3.14 *0.015
Speed = distance/ time
= 2*3.14*0.015/60
=0.00157 m/ s
= 1.57 x 10 ^-3 m/s.
Therefore , speed of the tip of second's hand of a watch of length 1.5 cm is 1.57 x 10 ^-3 m/s.
Answered by
123
Answer:
Explanation:
Angular speed = angular displacement/time.
angular displacement = 2πr/60sec.
r = length of second's hand = 1.5 cm.
= 2π * 1.5/60
=2 * 22/(7 * 40)
44/280.
=0.16cm/s
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