Question

when two resistors of resistance R1 and R2 are connected in parallel ,the net resistance is 3 ohm. when connected in series, its value is 16 ohm. Calculate the value of R1 and R2?

Answer 1

Explanation:

1/R1 + 1/R2 = 1/3

(R2 + R1)/R1.R2 = 1/3

• R1+R2 = 16 { given series}

so,

16/R1.R2 = 1/3

R1.R2 = 48