Physics, asked by rahulkumar4869, 11 months ago

Calculate the speed of the tip of second's hand of watch of length 1.5cm

Answers

Answered by sonuvuce
8

Answer:

The speed of he tip of the second's hand is 1.57 × 10^-3 m/s

Explanation:

Second's hand completes one revolution in 60 seconds

Thus time period T = 60 seconds

Angular velocity ω = 2π/T = 2× 3.14/60 = 0.105 radian/sec

Length of the second's hand R = 1.5 cm

                                                = 0.015 m

Therefore, radial velocity of the second's hand

\boxed{v=R\omega}

or, v = 0.015 × 0.105 m/s

       = 1.57 × 10⁻³ m/s

Hope this helps.

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