Calculate the standard deviation of the first 13 natural numbers
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1st 13 natural numbers are 1,2,3,4,5,6,7,8,9,10,11,12,13.
∑x=2n(n+1)
=213(13+1)
=213×14
∴ ∑x=91
Now, ∑x2=6n(n+1)(2n+1)
=613×14×27
∴ ∑x2=819
⇒ SD=n∑x2−(n∑x)2
=13819−(1391)2
=63−49
=14
=3.74Answer:
Step-by-step explanation:
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