Question

Calculate the standard
entropy change for the
reaction given below,
2 H202 (1) - 2 H20 (1) +
O2 (g);
The standard molar
entropy of reactants and
products are:
H202 (1) = 109.6 J/mol-K
H20 (1) = 69.9 J/mol-K
O2 (g) = 205 J/mol-K​

Answer 1

Answer:

• standard entropy change =284.4 J/mol-K

Explanation:

[ (2×109.6)-(2×69.9)+(205)] J/mol-K

= [219.2 - 139.8 +205] J/mol-K

= [424.2 - 139.8] J/mol-K

= 284.4 J/mol-K

So,

standard entropy change = 284.4 J/mol-K