Calculate the sulphate ion concentration in 0.15 m of h2 s o4
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Answer:
MSO2−4=0.150M
Explanation:
In solution, sodium sulfate dissociates according to the following equation:
Na2SO4(s)→2Na+(aq)+SO2−4(aq)
Therefore, 1mol of Na2SO4 will give 1mol of SO2−4 and thus, the molarity of sulfate ions will be equal to that of the sodium sulfate.
MSO2−4=0.150M
However, the molarity of sodium ions is the double of that of sodium sulfate since 1mol of Na2SO4 will give 2mol of Na+:
MNa+=0.300M
MSO2−4=0.150M
Explanation:
In solution, sodium sulfate dissociates according to the following equation:
Na2SO4(s)→2Na+(aq)+SO2−4(aq)
Therefore, 1mol of Na2SO4 will give 1mol of SO2−4 and thus, the molarity of sulfate ions will be equal to that of the sodium sulfate.
MSO2−4=0.150M
However, the molarity of sodium ions is the double of that of sodium sulfate since 1mol of Na2SO4 will give 2mol of Na+:
MNa+=0.300M
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