Math, asked by kmluke9562, 1 year ago

Calculate the sum of all such numbers possible by rearranging 3321?

Answers

Answered by RAMAN001
0
3321+3312+3123+3132+3213+3231+1233+1323+1332+2133+2313+2331=
Answered by aquialaska
0

Answer:

Sum of all numbers is 29997.

Step-by-step explanation:

We are given with a no. 3321

To find: Sum of all possible no. by rearranging 3321.

As we can see there are 4 digits in the given no, out of which two are same.

Then using permutation, first we find  no. of ways that we get after rearranging the digits.

\frac{4!}{2!}=\frac{4\times3\times2\times1}{2\times1}=4\times3=12

So, 12 nos we get after rearranging the digits are :

3321 , 3312 , 3123 , 3132 , 3213 , 3231 , 1233 , 1323 , 1332 , 2133 ,

2313 and 2331

Sum of these Nos. = 3321 + 3312 + 3123 + 3132 + 3213 + 3231 + 1233 +

                                  1323 + 1332 + 2133 + 2313 + 2331

                               = 29997

Therefore, Sum of all numbers is 29997.

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