Calculate the Sum of Money for Two Years
A sum of money fetches Rs. 4089 as compound interest at the rate of 4% per annum at the end of two years. What is the sum?
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T = P(1+r/100)^n when the interest is compounded.
and the compound interest is T-P.
Given T-P = 4089, we need to find P.
4089 = P(1+4/100)^2 - P
or 4089 = 1.0816P-P
or 4089 = 0.0816P
Thus, P = 4089/0.0816 = 50,110.29.
Therefore, for a principal of Rs. 50,110.29, the compound interest is Rs. 4089 at the end of 2 years at 4% rate per annum.
and the compound interest is T-P.
Given T-P = 4089, we need to find P.
4089 = P(1+4/100)^2 - P
or 4089 = 1.0816P-P
or 4089 = 0.0816P
Thus, P = 4089/0.0816 = 50,110.29.
Therefore, for a principal of Rs. 50,110.29, the compound interest is Rs. 4089 at the end of 2 years at 4% rate per annum.
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