the sum of the digit of a 2 digit no is 12 if the digit are reserved the new no decrease by 36 find the no
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Let the digits =a and b
So, number=10a + b
Here,a+b=12
or, a=12-b...(i)
AND
(10a+b)-(10b+a)=36
10a +b -10b -a =36
9a -9b =36
a-b=4
(12-b)-b=4 (From (i))
12 - 2b =4
2b = 12-4
2b = 8
b = 4
So, a =8
Therefore the number is : 84
So, number=10a + b
Here,a+b=12
or, a=12-b...(i)
AND
(10a+b)-(10b+a)=36
10a +b -10b -a =36
9a -9b =36
a-b=4
(12-b)-b=4 (From (i))
12 - 2b =4
2b = 12-4
2b = 8
b = 4
So, a =8
Therefore the number is : 84
Rhibhu:
hope that helps you!
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