calculate the sum of the first 1000 positive integers
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Answered by
2
sn=n/2(2a+(n-1)d)
an=1000
1000=1+(n-1)1
n=1000
sn=1000/2(2+999)
=500×1002
=501000
the sum is 501000
an=1000
1000=1+(n-1)1
n=1000
sn=1000/2(2+999)
=500×1002
=501000
the sum is 501000
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Answered by
2
sn=n/2(2a+(n-1)d)so,we want to find first 1000 positive no.
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