Question

Calculate the surface area of a hemispherical dome of a temple with radius 14m to be white washed from outside

Answer 1

r=14
surface area= 2πr²=2*22/7*196=1232 m²

Answer 2

Given:

The radius of the hemispherical dome=14m

To find:

The surface area of a hemispherical dome of a temple

Solution:

The surface area of a hemispherical dome of a temple is 1,232m².

We can find the area by following the given steps-

We know that the hemispherical dome is to be whitewashed from the outside.

This means that we need to calculate the curved surface area of the hemispherical dome.

The curved surface area of a hemisphere=2πR², where R is the radius of the hemisphere.

Curved surface area=2πR²

Putting the values,

Curved surface area=2π×14²

=2π×14×14

=2×22×14×14/7

=2×22×2×14

=88×14

=1,232m²

Therefore, the surface area of a hemispherical dome of a temple is 1,232m².