calculate the temp at which a solution contaning 54 g of glucose in 250g water will freeze ( Kf for water = 1.86mol-1 kg)
Answers
Answered by
0
Given: Mass of glucose = 54g Mass of water = 250 g Kf for water = 1.86 K kg mol-1 Molecular mass of glucose = 180.15 g/mol Using the relation: Now,Freezing point of solution = Freezing point of water − depression in freezing point Freezing point of solution = 273 − 2.23 = 270.77 KRead more on Sarthaks.com - https://www.sarthaks.com/579789/calculate-temperature-which-solution-containing-glucose-c6h12o6-water-freeze-water-mol1?show=580039#a580039
Similar questions