calculate the temperature at which the average speed of oxygen is equal to that of hydrogen
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Answer : 426.3K426.3K
Explanation :
3RT1M1−−−−−√=3RT2M2−−−−−√3RT1M1=3RT2M2
T1=M1M2.T2=3228×373=4263K
Explanation :
3RT1M1−−−−−√=3RT2M2−−−−−√3RT1M1=3RT2M2
T1=M1M2.T2=3228×373=4263K
Urooj7778:
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tysm
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